<PRE><B>Question 1059969</B>
 Determine four consecutive integers such that the sum of the first three integers is 20 more than the fourth integer 
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1st:: x-2
2nd:: x-1
3rd:: x
4th:: x+1
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Equation:
3x-3 = (x+1)+20
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2x = 24
x = 12
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1st:: x-2 = 10
2nd:: 11
3rd:: 12
4th:: 13
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Cheers,
Stan H.
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