Question 1059927
 Point A is found at (-3, -3). Find the cos at that point.
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cos = x/r
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Since r = sqrt[3^2+3^2] = 3*sqrt(2)
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Ans: cos(t) = -3/(3sqrt(2)) = -1/sqrt(2) = -sqrt(2)/2
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Cheers,
Stan H.
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A.) √2/2
B.) - 2√/2
C.) √3/3
D.) - √3/3