Question 1059900
(1/sin^2x)+ (sec^2x/tan^2x); sec^2 x=1/cos^2 x; tan^2 x= sin^2x/cos^2x; sec x/tan x=(1/sin^2 x)
Therefore, we have (1/sin^2x)+(1/sin^2 x)=2/(sin^2x)