Question 1059835
<pre><b>
I won't do it for you for that would be totally dishonest, but I'll
be a little bit dishonest.  This is what you must solve for P
to get the answer to the first part.

{{{(P(1+0.03/4)^(4*5)+5000)e^(0.055*7)}}}{{{""=""}}}{{{10078.46}}}

To get the answer to the second part, substitute what you
get for P in the blank below, replace the 7 by T, and put
9000 on the right side, and solve for T. That is, fill in the
blank with what you got for P above in this:

{{{("_____"(1+0.03/4)^(4*5)+5000)e^(0.055*T)}}}{{{""=""}}}{{{9000}}}

The whole part of the number you get for T is the number of full 
years after Jan 1, 2005. The decimal part is the fraction of the 
next year after that.

Multiply that decimal part by 365.25 to get the number of days into 
that next year that the amount was $9000.  Then use the number of 
days in the various months to find out just what date that was.

Luck to you!

Edwin</pre>