Question 1059785
Solve this system using elimination.
First, look and see if you can easily multiply either equations to get a set of opposite or "same" coefficients.
4x is a factor of 8x, so you can multiply the second equation by 2.
2(4x - 3y = 14)
Your system should now look like:
8x + 7y = -11
8x - 6y = 28
The x's now have the same coefficients, so this means we need to subtract the equations. 
The x's WILL CANCEL
7y - (-6y) = 7y + 6y = 13y
-11 - 28 = -39

Now, we are left with...

13y = -39

Solve for "y". Divide by 13 on both sides.

y = -3

Plug in -3 for "y" in either equation to solve for "x"

4x - 3(-3) = 14
Multiply -3 and -3 together.
4x + 9 = 14
Subtract by 9 on both sides
4x = 5
Divide by "4" on both sides.
x = 5/4

Your solution in (x,y) form is now (5/4,-3).

ALWAYS plug in your solution into your systems (ORIGINAL EQUATIONS!) to check your answer.

Plug in 5/4 for x, and -3 for y.

Does 8(5/4) + 7(-3) equal -11?
Let's check.
8*5/4 = 40/4 = 10

10 + 7(-3) 
7*-3 = -21

10 + (-21)
10 - 21 = -11 
YES! This solution works for this equation, but we still need to try the other!

Does 4(5/4) - 3(-3) equal 14?
Let's check!
4*5/4 = 20/4 = 5

5 - 3(-3)
-3*-3 = 9
5 + 9 = 14
YES! Our solution works for BOTH equations aka the SYSTEM. This is a CORRECT solution!