Question 1059623
1.{{{J=K/3}}}
2.{{{L=5J}}}
3.{{{L-K=24}}}
From 1 and 2,
{{{L=(5/3)K}}}
Substituting into 3,
{{{(5/3)K-K=24}}}
{{{(2/3)K=24}}}
{{{K=36}}} 
So then,
{{{J=36/3}}}
{{{J=12}}}
and
{{{L=5(12)}}}
{{{L=60}}}