Question 1059698
{{{6y=-2x-5}}}
{{{y=-(1/3)x-5/6}}}
Perpendicular lines have slopes that are negative reciprocals,
{{{m[1]*m[2]=-1}}}
{{{m[2]=3}}}
So then using the point-slope form,
{{{y-3=3(x-(-3))}}}
{{{y-3=3x+9}}}
{{{y=3x+12}}}
{{{3x-y=-12}}}