Question 1059555
I might be mistaken but the geometry of the base is impossible:

If the perimeter of an equilateral triangle is 1.2ft, then each side is 0.4ft
The area of that triangle is given as 0.6 sqft

For the base:  {{{ Area = (1/2)(b)(h) }}}
                     {{{ Area = 0.6 = (1/2)(0.4)(h) }}}
                     {{{             3 = h }}}

Do you see it?

If the height of the base triangle is 3, then there is a triangle that corresponds to half of the base of the pyramid that has sides:   3, 0.2, and 0.4.   You can not have a triangle with these dimensions (the two short sides must add to more than 3 or else they do not form a closed shape).
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As a further check:  Area of equilateral triangle is  {{{ (sqrt(3)/4)*side^2 }}}
                                    {{{ (sqrt(3)/4)*(0.4^2) = 0.06928  <> 0.6  }}}