Question 92661
One number is 8 less than another.  If 9 times the smaller number minus 4 times the larger number is 8, find the two numbers

Let the first number be x and the second be y then:
x < y by 8 ..............>  
 y - x  = 8         (1)
9x - 4y = 8        (2)

9y - 9x = 72       (1)
9x - 4y = 8        (2)

by addition: 5y = 80
divide by 5: y = 16
substitute in eq (1) we get:
16 - x  = 8    So, x = 16 - 8 = 8
the two numbers are : 8 and 16