Question 1059413
{{{ln(60(e^(-0.11t)))=ln(10)}}}
Use your log rules,
{{{ln(60)+ln(e^(-0.11t))=ln(10)}}}
{{{-0.11t=ln(10)-ln(60)}}}
{{{t=(ln(60)-ln(10))/0.11}}}
{{{highlight(t=ln(6)/0.11)}}}