Question 1059270
Let {{{ d }}} = the one-way distance of the trip in miles
Let {{{ t }}} = the plane's time in hrs
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Equation for flying with the wind
(1) {{{ d = 225t }}}
Equation for flying against the wind
(2) {{{ d = 180*( 5 - t ) }}}
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By substitution:
{{{ 225t = 180*( 5 - t ) }}}
{{{ 225t = 900 - 180t }}}
{{{ 405t = 900 }}}
{{{ t = 20/9 }}} hrs
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(1) {{{ d = 225*( 20/9) }}}
(1) {{{ d = 500 }}}
{{{ 2d = 1000 }}}
The plane can fly 1000 miles
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check:
(2) {{{ d = 180*( 5 - t ) }}}
(2) {{{ d = 180*( 5 - 20/9 ) }}}
(2) {{{ d = 180*( 45/9 - 20/9 ) }}}
(2) {{{ d = 180*( 25/9 ) }}}
(2) {{{ d = 500 }}}
OK