Question 1059239
{{{ ln( x^2 + 1 ) - ln( x - 1 ) = 1 + ln( x + 1 ) }}}
{{{ ln( ( x^2 + 1 )/( x - 1 ) ) = ln( e )  + ln( x + 1 ) }}}
{{{ ln( ( x^2 + 1 )/( x - 1 ) ) = ln( ( x + 1 )*e ) }}}
{{{ ( x^2 + 1 ) / ( x - 1 ) = ( x + 1 )*e }}}
{{{ x^2 + 1 = ( x^2 - 1 )*e }}}
{{{ ( e - 1 )*x^2 = e + 1 }}}
{{{ x^2 = ( e + 1 ) / ( e - 1 ) }}}
{{{ x = sqrt( ( e + 1 ) / ( e - 1 ) ) }}}
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