Question 1059210
Suppose that a population is known to be normally distributed with 
mu equals = 2,100 
and 
sigma equals = 240. 
If a random sample of size n equals = 8 is​ selected, 
calculate the probability that the sample mean will exceed 2,200.
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z(2200) = (2200-2100)/[240/sqrt(8)] = 1.1785
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P(x-bar > 2200) = P(z > 1.1785) = normalcdf(1.1785,100) = 0.1193
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Cheers,
Stan H.
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