Question 1059107
There are 36 possible outcomes from the roll of two six-sided dice.


There are three outcomes that have a sum which is greater than 10:


(5, 6), (6, 5), and (6, 6)


The probability that the sum of the two numbers is greater than 10 
is then:


(Number of outcomes > 10 / Total number of possible outcomes) = 3/36 = 1/12