Question 1058902
It's a straight line.
Both {{{ x }}} and {{{ y }}} are 1st degree,
meaning their exponent is {{{ 1 }}}
You could write it as:
{{{ 12*y^1 - 8*x^1 = 12 }}}
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If I put it into the slope-intercept form, 
I can plot it:
{{{ 12y - 8x = 12 }}}
{{{ 12y = 8x + 12 }}}
{{{ y = (2/3)*x + 1 }}}
{{{ graph( 400, 400, -10, 10, -10, 10, (2/3)*x + 1 ) }}}