Question 1058856
Three points not on a straight line define a quadratic function.
Since we have two zeros of the function, we know it is not linear,
so the factories form must be
{{{f(x)=a(x+4)(x-1)}}}
For {{{x=-2}}} we must have {{{f(-2)=-2}}} , so
{{{a(-2+4)(-2-1)=-2}}}
{{{a*2*(-3)=-2}}}
{{{-6a=-2}}}
{{{a=(-2)/(-6)}}}
{{{a=1/3}}}
So the function is
{{{f(x)=(1/3)(x+4)(x-1)}}} .