Question 1058847
I am assuming the problem is to find log base8 of 27, in terms of a.

{{{log2(3) = a  }}}  so

{{{ log8(3) = a/3 }}}       because   8^(a/3) = (2^3)^(a/3) = 2^(a) 

Therefore:
{{{ log8(27) = log8(3^3) = 3*log8(3) = 3*(a/3) = a }}}