Question 1058807
One can use synthetic division on each of the factors that make up x^2-x-2, (x-2)(x+1)
2/1===-6---3---10
--1===-4==-5==0
-1/1===-6==3==10
==1===-7==10==0
one can use long division, too.
========x-5
x^2-x-2/x^3-6x^2+3x+10
======x^3-x^2-2x
========-5x^2+5x+10
========-5x^2+5x+10
change signs and remainder is 0
The third factor is (x-5).