Question 92587
Use the Pythagorean Theorem
{{{a^2+b^2)}}}={{{(c^2)}}}
{{{2^2+b^2)}}}={{{(6^2)}}}
{{{(4+b^2)}}=36
(((b^2+4)}}}=36
{{{(b^2)}}}=36-4
{{{(b^2)}}}=32
{{{(sqrt(b^2))}}}={{{(sqrt(32))}}}
b=5.6568=5.66