Question 1058789
 Log (x+3)+Log (x-2)=Log14
 Log((x+3)*(x-2)) = Log14
 Log((x+3)*(x-2)) = Log(14)
x^2 + x - 6 = 14
x^2 + x - 20 = 0
(x+5)*(x-4) = 0
x = -5 ** rejected, gives log of a negative value.
x = 4