Question 1058789
Using the logarithm law log(a) + log(b) = log(ab) gives:


log((x+3)(x-2)) = log(14)


Taking the antilog of both sides gives:


(x + 3)(x - 2) = 14


x^2 + x - 6 = 14


x^2 + x - 20 = 0


(x +5)(x - 4) = 0


x = -5, x = 4


Since the log function is not defined for values less than 0, the
x = -5 solution is discarded because -5 + 3 = -2 and -5 - 2 = -7.


The only solution that works is x = 4.