Question 1058629

2. Two numbers are such that if the square of the first number is subtracted by twice their product, the difference is -1. But twice the product added to the sum of thrice the square of the first number and five times that number gives 10.
<pre>Let 1st number be F, and 2nd, S
Then, {{{2FS - F^2 = - 1}}} ------- eq (i)
Also, {{{2FS + 3F^2 + 5F = 10}}} ------ eq (ii)
{{{4F^2 + 5F = 11____4F^2 + 5F - 11 = 0}}} ------ Subtracting eq (ii) from eq (i)
Solve the above quadratic equation to get: {{{highlight_green(matrix(3,1, matrix(1,9, 1^(st), number, "=", 1.14718086, when, 2^(nd), number, "=", 0.137739364), "OR", matrix(1,9, 1^(st), number, "=", - 2.39718086, when, 2^(nd), number, "=", - 0.990012092))))}}}