Question 1058701
{{{f(x)=-2/x}}}, domain excludes x=0.


I(x) can be the inverse of f(x).

{{{I(f(x))=f(I(x))}}}


{{{f(I(x))=-2/I(x)=x}}}
{{{-I(x)/2=1/x}}}
{{{I(x)=-2(1/x)}}}
{{{I(x)=-2/x}}}------again, domain {{{x<>0}}}.