Question 1058198
random, proportional to number, could be infinite, discrete
Poisson distribution with parameter 0.3
e^(-lambda)*lambda^x/x!
For 0, it is e^(-0.3)=0.7408
for 1 it is 0.7408(0.3)=0.2222
for 2 it is 0.7408*(0.3^2)/2=0.0334