<PRE><B>Question 1058606</B>
describe graph of quadratic function f(x)=x^2+10x+12 and identify the vertex and the x intercepts(smaller x value and larger x value).
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vertex occurs when x = -b/(2a) = -10/(2) = -5
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f(-5) = 25 - 50 + 12 = 13
Vertex:: (-5,13)
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x-intercepts::
Solve x^2 + 10x + 12 = 0
x = [-10 +- sqrt(100 - 4*12)]/2
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x = [-10 +- sqrt(52)]/2
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Cheers,
Stan H.
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