Question 1058595
a.  The answer is b,
The best estimate is the sample mean of 18 eggs/mo.
98% CI interval width is t(df=18,0.99)s/sqrt(n); t=2.552.
That is 2.552*4/sqrt(19)=2.342
(15.66, 20.34)
Yes, it would be reasonable, because 19 is in the interval.
No, because 24 is not in the interval.