Question 1058581
Solving the first equation for y gives:


y = 2x - 1


Substituting 2x - 1 in place of y in the second equation then gives:


x + (2x - 1) = -1


x + 2x - 1 = -1


3x - 1 = -1


3x = -1 + 1


3x = 0


x = 0


Then, with x = 0


y = 2x - 1 = 2(0) - 1 = -1


Solution: x = 0, y = -1