<PRE><B>Question 1058515</B>
Poisson distribution--discrete, proportional to time, theoretically could be infinite, random.
8 calls in 10 minutes is the proportion. That is the parameter.  p(x)=e^(-lambda)*lambda^x/x!
So for 4, it is e^(-8)*8^4/4!=0.0573
For 12 calls in 20 minutes, expected is 16
e^(-16)16*12/12!=0.0661
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expected calls in five minutes is 1/12 of an hour during which 48 calls are received.  I would expect 4 calls.
probability that none is waiting is e^(-4)*4^0/0!=e^(-4)=0.0183
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For 3 minutes without a call it would be an expectation of 2.4 (1/20 th of 48)
e^(-2.4)=0.0907
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