Question 1058553
This expression cannot be factored "nicely".


Assuming that you are looking for solutions to:


2x^2 + 3x - 1 = 0


you will need to use the Quadratic Formula to solve
for x:


{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}


with a = 2, b = 3, and c = -1.


Making those substitutions gives:


{{{x = (-3 +- sqrt( 3^2-4*2*(-1) ))/(2*2) }}}


{{{x = (-3 +- sqrt( 17 ))/4 }}}


Solutions: {{{highlight(x = (-3 - sqrt( 17 ))/4) }}}, {{{highlight(x = (-3 + sqrt( 17 ))/4) }}}