Question 1058522
The required sample size is:


{{{n = (p)(1 - p)(z/E)^2}}}


For a 92% confidence level, use z = 1.751.


The value of E is 0.04.


Since we don't know anything about the population percentage that will 
pay extra for the options, use p = 0.5 as a conservative estimate.


The required sample size is then:


{{{n = (0.5)(1 - 0.5)(1.751/.04)^2}}}


n = 479.06


Since this is a minimum value, and the sample size must be a whole number, 
this result must be rounded up to the next whole number.


Solution: Sample size = 480