Question 1058499
(1) {{{ y = 2x + 1 }}}
(2) {{{ y = x^2 - 2 }}}
----------------------
Subtract (1) from (2)
(2) {{{ y = x^2 - 2 }}}
(1) {{{ -y = -2x - 1 }}}
-----------------------
{{{ 0 = x^2 - 2x - 3 }}}
{{{ ( x - 3 )*( x + 1 ) = 0 }}} ( by inspection )
--------------------------
{{{ x = 3 }}} and {{{ x = -1 }}} 
are the solutions
--------------------------
Plug both solutions into either (1) or (2)
{{{ x = 3 }}}
(1) {{{ y = 2*3 + 1 }}}
(1) {{{ y = 7 }}}
One intersection is ( 3, 7 )
----------------------------
{{{ x = -1 }}}
(1) {{{ y = 2*(-1) + 1 }}}
(1) {{{ y = -1 }}}
2nd intersection is ( -1, -1 )
-----------------------------
Here's the plot:
{{{ graph( 400, 400, -6, 6, -6, 10, 2x + 1, x^2 - 2 ) }}} 
My solutions look OK