Question 1058477

Let
 n = number of nickels
 d = number of dimes
 q = number of quarters

….

5n + 10d + 25q = 465    (total value, in cents)
d = n + 5                         (5 more dimes than nickels)
q = n + 7                         (7 more quarters than nickels)

The easiest thing to do at this point is to substitute for d & q in the top equation.

5n + 10(n+5) + 25(n+7) = 465

Can you solve for n?