Question 1058487
Use a general quadratic equation and solve using three of the given points.
{{{y=ax^2+bx+c}}}
So using (0,350),
{{{350=a(0)^2+b(0)+c}}}
{{{c=350}}}
(1,353)
{{{353=a(1)^2+b(1)+350}}}
1.{{{a+b=3}}}
(2,382)
{{{382=a(2)^2+b(2)+350}}}
{{{4a+2b=32}}}
2.{{{2a+b=16}}}
Subtracting 1 from 2,
{{{2a+b-a-b=16-3}}}
{{{a=13}}}
Then use either equation,
{{{13+b=3}}}
{{{b=-10}}}
So,
{{{y=13x^2-10x+350}}}