Question 1058485
Convert to vertex form,
{{{y=-2x^2+32x-12}}}
{{{y=-2(x^2-16x)-12}}}
{{{y=-2(x^2-16x+64)-12+2(64)}}}
{{{y=-2(x-8)^2-12+128}}}
{{{y=-2(x-8)^2+116}}}
The vertex is (8,116) and the parabola opens downwards.
{{{y[max]=116}}}
Range is ({{{-infinity}}},{{{116}}}]