Question 1058479
{{{P(X)=C(12,X)*(0.15)^X*(1-0.15)^(12-X)}}}
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Using EXCEL to generate numbers,
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*[illustration lp22.JPG].
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{{{P(X>1)=P(2)+P(3)+P(4)+P(5)+P(6)+P(7)+P(8)+P(9)+P(10)+P(11)+P(12)}}}
or
{{{P(X>1)=1-P(0)-P(1)}}}
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So,
{{{P(X>1)=0.55654}}}