Question 1058386
Let x represent the first number, and x + 6 represent the second number.


Then "six times the first is 3 more than 3 times the second" can be written as the 
following equation:


6x = 3(x + 6) + 3


Expanding the terms on the right side gives:


6x = 3x + 18 + 3


6x = 3x + 21


6x - 3x = 21


3x = 21


x = 7


The first number is 7.


The second number is x + 6 = 7 + 6 = 13.