Question 1058297
{{{y=p*2^(t/6)}}}
When t reaches 6 days, exponent is 1, and the factor applied is 2.  This is how p becomes doubled.  


Next, use July 5 as t=0.  p=26.
{{{highlight(y=26*2^(t/6))}}}--------your model.



{{{graph(400,400,-5,30,-5, 120,26*2^(x/6))}}}
Not the best graph appearance.  Try using google for a better display, or a graphing calculator.