Question 1058361
Let's start with the difference in means first.
Null Hypothesis-{{{Ho}}}:{{{u[A]=u[B]}}} or {{{u[A]=u[B]}}}
Alternate Hypothesis-{{{Ha}}}:{{{u[A]<>u[B]}}}
{{{alpha=0.05}}}
Use unpooled standard deviation method,
{{{t=(29.5-30.3)/sqrt(0.7^2/10+0.5^2/9)=-2.887 }}}
{{{C= ((0.7)^2/10)/((0.7)^2/10+(0.5)^2/9)=0.6382 }}}
{{{DOF=((10-1)(9-1))/((9-1)(0.6238)+(1-0.6238)^2(10-1))=11.494}}}
Rounding down,
{{{DOF=11}}}
Checking the critical t value for {{{DOF=11}}} and {{{alpha=0.05}}}.
{{{t[c]=-2.201}}}
Since {{{t<t[c]}}}, reject the null hypothesis. 
The sample means are significantly different.
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With regards to the variances, are you supposed to use a particular test to check. F test?
In this case,
{{{F=s[1]^2/s[2]^2=(0.7/0.5)^2=1.96}}}
I used EXCEL with {{{X=1.96}}},{{{DOF[1]=9}}} and {{{DOF[2]=8}}} to get a p value of {{{0.356}}}.
Since {{{0.356>0.05}}}, there is no significant difference between the samples using the variances.