Question 1058348
{{{z=kx^2y^2}}}
So,
{{{k=z/(xy)^2}}}
and
{{{55/(3*5)^2=z/(2*5)^2}}}
{{{z=55*((2*5)^2/(3*5)^2)}}}
{{{z=55*(4/9)}}}
{{{z=220/9}}}