Question 1058354
When the population grows by a fixed value of 6,000 people per year:


P(t) = 150,000 + 6,000t


where t is the number of years from the current time.


When the population grows by 6% per year:


P(t) = 150,000(1.06)^t


With the population growing by 6% per year, the population in 
two years will be:


P(2) = 150,000(1.06)^2 = 168,540