Question 1058308
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<pre>
  {{{sqrt(27)*x^2 - sqrt(48)*x + 2*sqrt(75)*x^2}}} = 

= {{{3*sqrt(3)*x^2 - 4*sqrt(3)*x + 2*5*sqrt(3)*x^2}}} = 

= {{{13*sqrt(3)*x^2 - 4*sqrt(3)*x}}} =

= {{{sqrt(3)*x*(13x -4)}}}.
</pre>

Hey, I really don't know if x^2 is under the square root.


In my calcs I supposed it is not.


If I was wrong, it is your fault, not my.