Question 1058261

Please help me solve this 3 variable system:
x+y+z=8
x-y/3+(4/3)z=7
3z-3y-2x=7
<pre>x + y + z = 8 -------- eq (i)
{{{x - y/3 +(4/3)z = 7}}} ------ eq (ii)
3z - 3y - 2x = 7_____- 2x - 3y + 3z = 7 ----- eq (iii)
3x + 3y + 3z = 24 ---- Multiplying eq (i) by 3 ------- eq (iv)
3x - y + 4z = 21 ----- Multiplying eq (ii) by 3 ------ eq (v)
   x  + 6z = 31 ------ Adding eqs (iii) & (iv) ------- eq (vi)
  4x  + 5z = 29 ------ Adding eqs (i) & (v) ---------- eq (vii)
- 4x - 24z = - 124 --- Multiplying eq (vi) by - 4 ---- eq (viii)
- 19z = - 95 --------- Adding eqs (viii) & (vii)
{{{highlight_green(matrix(1,3, z = (- 95)/(- 19), or, 5))}}}

x + 6(5) = 31 ----- Substituting 5 for z in eq (vi)
x + 30 = 31
{{{highlight_green(matrix(1,5, x, "=", 31 - 30, or, 1))}}} 

1 + y + 5 = 8 ------ Substituting 1 for x, and 5 for z in eq (i)
6 + y = 8
{{{highlight_green(matrix(1,5, y, "=", 8 - 6, or, 2))}}}