Question 1056260

The length of a rectangle is 13 centimeters less than four times its width. Its area is 35 square centimeters. Find the dimensions of the rectangle.
<pre>Let width be W
Then length = 4W - 13
We then get the following AREA equation: W(4W - 13) = 35
{{{4W^2 - 13W = 35}}}
{{{4W^2 - 13W - 35 = 0}}}
(W - 5)(4W + 7) = 0----- Factoring the TRINOMIAL
W, or width = {{{highlight_green(matrix(1,2, 5, cm))}}}         OR        {{{W = (- 7)/4}}} (ignore)
Length: {{{highlight_green(matrix(1,4, 35/5, or, 7, cm))}}}