Question 1058234
x1=(1/2a)(-b+ sqrt(b^2-4ac))
x2=(1/2a)(-b-sqrt(b^2-4ac))
Their sum is (1/2a)(-2b)=-b/a
Their product is foiling a difference of squares.
That is (1/4a^2)*{b^2-(b^2-4ac)}=4ac/4a^2=c/a, a NE 0