Question 1058182
Let:
   n = smallest of the 3 odd numbers
   n + 2 = 2nd consecutive odd number
   n + 4 = 3rd consecutive odd number

"Twice the sum of the 1st and 2nd" is
 2((n)+(n+2))

"One less than 3 times the 3rd" is
 3(n+4) - 1

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Set the two equal:
{{{ 2((n) + (n+2)) = 3(n+4)-1 }}} 
{{{  4n + 4 = 3n + 12 - 1 }}}
{{{   n = 7 }}}

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Ans: The three odd numbers are 7, 9, and 11
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Check:
   2(7+9) = 32
   3(11) - 1 = 32   (ok)