Question 1058162
The volume described in this problem is a truncated rectangular pyramid.


The volume is given by:


{{{V = (1/3)(A1 + A2 + sqrt(A1 * A2))(h)}}}


where A1 is one base area, A2 is the other base area (it doesn't matter which is which),
and h is the height.


For this problem:


A1 = 180 * 20 = 3600


A2 = 216 * 24 = 5184


h = 15


The volume is then:


{{{V = (1/3)(3600 + 5184 + sqrt(3600 * 5184))(15) = 65520}}}


Converting 62,520 cubic feet to cubic yards gives:


(65520 cu ft)(1 cu yd / 27 cu ft) = 2,426.67 cubic yds