Question 1058147
{{{log(2,(1/6))}}}


{{{log(2,(6^(-1)))}}}


{{{-1*log(2,6)}}}


Change Of Base Formula:
Put into base 10.


{{{log(10,6)/log(10,2)=log(2,6)}}}
-
{{{-1*log(10,6)/log(10,2)}}}


{{{-1(0.77815/0.30103)}}}


{{{highlight(-2.585)}}}