Question 1058147
The change of base formula is:


 *[illustration Change_of_Base]


where "log" is the common base-10 logarithm, and "ln" is the 
base-e natural logarithm. You can use either one.


To evaluate log2 (1/6) then:


log2 (1/6) = log(1/6) / log(2) ≈ -2.5850


As a check, {{{2^-2.5850 = 0.1666 = 1/6}}}