Question 1058122
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the area of the floor of a rectangular room is 60 square meters. if the perimeter of the floor is 34 meters, 
what are the dimensions of the floor ( solve algebraically)
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<pre>
Let L be the length (in meters), and W be the width. Then

2L + 2W = 34,

hence

L + W = 17.

Then W = 17-L.

The area is 

A = L*W = L*(17-L) = {{{17L - L^2}}}.

Thus you have an equation 

{{{17L - L^2}}} = 60,   or

{{{L^2 - 17L + 60}}} = 0.

Factor the left side:

(L-5)*(L-12) = 0.

The roots are 5 and 12.

The length is 12 meters, The width is 5 meters.
</pre>

Solved.


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&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/Surface-area/Problems-on-the-area-and-the-perimeter-of-a-rectangle.lesson>Problems on the area and the dimensions of a rectangle</A>

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