Question 1058067
Let n be the first odd number. Then the next numbers in sequence will be n+2 and n+4. So:
n(n+4)=2(n+2)+11
nē+4n=2n+15
nē+2n-15=0
(n+5)(n-3)=0
n=3 or -5 
Throwing out the negative answer, we get the consecutive odd numbers as 3, 5, and 7. ☺☺☺☺